Counting how many even and odds are there

            main()  
            {  
                int k, no, e = 0, d = 0;  
                clrscr();  
            
                for(k = 1; k <= 10; k = k + 1)  
                {  
                    printf("\n Enter any number: ");  
                    scanf("%d", &no);  
            
                    if(no % 2 == 0)  
                    {  
                        e = e + 1;  
                    }  
                    else  
                    {  
                        d = d + 1;  
                    }  
                }  
            
                printf("\n %d evens are there", e);  
                printf("\n %d odds are there", d);  
            
                getch();  
            }  
            
            

Output: